We have been exploring various R packages for handling text for natural language processing. In this twenty-third article in the R, Statistics and Machine Learning series, we delve into the ‘stringr’ package, which provides a comprehensive set of functions to easily work with strings.
do you know any ready-to-use method to obtain length and also overlap of two strings? However only with R, maybe something from stringr? I was looking here, unfortunately without s
I read up on regular expressions and Hadley Wickham's stringr and dplyr packages but can't figure out how to get this to work. I have library circulation data in a data frame, wit
I'm working with stringr, but the solution doesn't have to be. In the following string I want to replace all the spaces that have a letter to their left and right (i.e. first 2) w
word:12335 anotherword:2323434 totallydifferentword/455 word/32 I need to grab the character string before the : or / using only base R functions. I can do this using stringr but
I would like to replace a part of a string (between the first 2 underscores, the first group always being 'i') like in the base R example below: library(dplyr) library(stringr) d
I have the following code in R to get the recent tweets about the local mayor candidates and create a wordcloud: library(twitteR) library(ROAuth) require(RCurl) library(stringr) li
I am trying to get the number of open brackets in a character string in R. I am using the str_count function from the stringr package s<- '(hi),(bye),(hi)' str_count(s,'(') Er
What do these expressions mean? Where can I learn about their usage? \\d \\D \\s \\S \\w \\W \\t \\n ^ $ \ | etc.. I need to use the stringr package and i have ab
I'm trying to extract twitter handles from tweets using R's stringr package. For example, suppose I want to get all words in a vector that begin with 'A'. I can do this like so lib
I looking for a way to efficiently apply a function to each row of data.table. Let's consider the following data table: library(data.table) library(stringr) x <- data.table(a =
I am trying to replace both 'st.' and 'ste.' with 'st'. Seems like the following should work but it does not: require('stringr') county <- c('st. landry', 'ste. geneveve', 'st.
I have the following data frame: df <- data.frame(city=c('in London', 'in Manchester city', 'in Sao Paolo')) I am using str_extract and return the word after 'in' in a separate
I'm trying to find an effective way to extract words from an text column in a dataset. The approach I'm using is library(dplyr) library(stringr) Text = c('A little bird told me ab
There is this strange behavior of stringr, which is really annoying me. stringr changes without a warning the encoding of some strings that contain exotic characters, in my case ø
I am trying to use non-capturing groups with the str_extract function from the stringr package. Here is an example: library(stringr) txt <- 'foo' str_extract(txt,'(?:f)(o+)') T